Dear Arley, There is a very precise way to control for the audibility of sound. Useful for both screening the potential subjects, as well as calculating how much you may need to increase the sound level to make it audible. This procedure forms one of the the basics of the SII protocol (ANSI S3.5 1997) and it is discussed in detail in the article Pavlovic, C.V. "Derivation of primary parameters and procedures for use in speech intelligibility predictions," JASA 1987. The article and the standard are relatively complex, and you may want to resort to the following procedure where the goal is to see where on the average across time the sound is below or above threshold. If you are dealing with short impulsive stimuli the accuracy of the procedure may be compromised. A. In Table 4 of the Standard locate "Reference Internal Noise Spectrum Level" for octave frequencies between 250 and 8000 Hz. These values correspond to 0 dB HL. Call this value A. B. Measure for each of the octaves the average dB SPL for your environmental sounds using a sound level meter at the position of the listener with the listener absent. Call this value B. (B-A is now how much the sound is above the normal threshold). C. Measure for each octave frequency the hearing loss of the person using an audiometer. If the test you are doing is for binaural listening and the sound is in front, use the better ear threshold. If the thresholds are identical decrease the threshold you measured by 2 dB. If the sounds are coming from all around the listener I strongly suggest you limit the test to symmetrical hearing loss only and do not use the 2 dB correction. Call this value C. When you have these three values for each octave frequency, then the level of the Signal relative to the Actual Threshold is; (B - A) - C = B - A - C. For example at 1000 Hz: You will find in the Table 4, that the internal noise that corresponds to 0 dB HL is: A = -12.5 dB SPL You measure the environmental signal to be B = 25 dB SPL You measure the Left and Right ear thresholds to be 30 dB HL. Since they are identical, you will take the binaural threshold C = 30-2 = 28 dB HL Now, B - A - C = 25 + 12.5 - 28 = 9.5 dB (not dB SPL). That is the Sound is 9.5 dB above the threshold. Normally, the sound is variable, and you may want some estimate of that variability as well. Best of luck. Chas Chas (Caslav, Chaslav) Pavlovic
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