Re: Multifrequency Tympanometry

["reinifrosch@xxxxxxxxxx" <reinifrosch@xxxxxxxxxx>]

Hello Navid and List,

A technical comment:

The resonance frequency is proportional to the square root 
of the stiffness, and indirectly proportional to the square root 
of the mass.

Example: 

A sphere of mass M on a spring of stiffness (i.e., spring 
constant) S. 

In the SI (système international), the dimension
of M is kg, and that of the spring constant S is N/m 
(Newtons per metre). 

Tne Newton is the unit of force, i.e., of mass times
acceleration, and thus is equal to one kg * m / s^2.

So the dimension of the stiffness S is kg / s^2, and that of 
the square root of (S/M) is 1/s, equal to the dimension of 
frequencies.

Reinhart Frosch.

Reinhart Frosch,
Dr. phil. nat.,
r. PSI and ETH Zurich,
Sommerhaldenstr. 5B,
CH-5200 Brugg.
Phone: 0041 56 441 77 72.
Mobile: 0041 79 754 30 32.
E-mail: reinifrosch@xxxxxxxxxx .

----Ursprüngliche Nachricht----
Von: nshahnaz@xxxxxxxxxxxxxxxxxx
Datum: 14.10.2006 18:06
An: <AUDITORY@xxxxxxxxxxxxxxx>
Betreff: Re: Multifrequency Tympanometry

Hi 

[...] Resonant frequency is directly proportional to the 
square of stiffness and indirectly proportional to the 
effect of mass. [...]